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数学物理方法 2025-1

复变函数-2025-1

数学物理方程-2025-1

1. 考虑两端固定的弦在初始激励下的自由振动,即是给定初始位移和初始速度,求以后各时刻的位移 u(x,t)u(x,t)。定解问题为

2ut2a22ux2=0,(0<x<l, t>0)(1a)\frac{\partial^2 u}{\partial t^2} - a^2 \frac{\partial^2 u}{\partial x^2} = 0, \quad (0 < x < l,\ t > 0) \tag{1a} ux=0=0,ux=l=0,(t0)(1b)u\big|_{x=0} = 0,\quad u\big|_{x=l} = 0, \quad (t \ge 0) \tag{1b} ut=0=φ(x),utt=0=ψ(x),(0xl)(1c)u\big|_{t=0} = \varphi(x),\quad \left.\frac{\partial u}{\partial t}\right|_{t=0} = \psi(x), \quad (0 \le x \le l) \tag{1c}

其中 φ(x)\varphi(x)ψ(x)\psi(x) 是已知函数,分别给出弦上各点的初始位移和初始速度。

Fixed–ends string (Fourier animation)
Space: x ∈ [0,l]. Ends fixed at x=0,l.
Wave speed a
Length l
Modes N
Vertical scale (px)
Time speed ×
Resolution (x points)
ϕ(x) preset
ψ(x) preset
x₀ (for pluck / Gaussian)
σ (Gaussian width, fraction of l)
ϕ amplitude
ψ amplitude
Custom ϕ(x) — use x, l, Math.*
Custom ψ(x) — use x, l, Math.*
Ready.

2. 考虑弦振动问题,x=0x = 0 端固定,x=lx = l 端作已知的简谐振动 AsinωtA \sin \omega t(其中振幅 AA 很小),弦的初始位移和初始速度均为零,且不受外力作用,求解弦的振动。定解问题为

2ut2a22ux2=0,(0<x<l, t>0)(51a)\frac{\partial^2 u}{\partial t^2} - a^2 \frac{\partial^2 u}{\partial x^2} = 0, \quad (0 < x < l,\ t > 0) \tag{51a} ux=0=0,ux=l=Asinωt,(t0)(51b)u\big|_{x=0} = 0,\quad u\big|_{x=l} = A \sin \omega t, \quad (t \ge 0) \tag{51b} ut=0=0,utt=0=0,(0xl)(51c)u\big|_{t=0} = 0,\quad \left.\frac{\partial u}{\partial t}\right|_{t=0} = 0, \quad (0 \le x \le l) \tag{51c}
Driven string (boundary forcing)
Space: x ∈ [0,l]. Left end fixed at x = 0, right end driven: u(l,t) = A sin(ω t).
Wave speed a
Length l
Drive amplitude A
Drive frequency ω
Modes N
Resolution (x points)
Vertical scale (px)
Time speed ×
Ready.