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Complex Turning Points, Resonances, and Non-Hermitian Problems

For a real confining potential, the words “left-decaying” and “right-decaying” almost specify the spectral problem by themselves. In the complex plane they do not. One must say along which contour the ODE is solved, in which sectors its ends lie, which WKB branch is subdominant at each end, and how those data move when EE, \hbar, or a coupling is continued.

That extra geometry is not a technical afterthought. The same analytic differential expression can support a self-adjoint bound-state problem, an outgoing resonance problem, or a non-Hermitian problem with a real spectrum. Their turning points may be identical. What changes is the pair of boundary lines selected in the two-dimensional solution space.

This page develops a single determinant language for all three cases. It then calibrates the language twice: the inverted oscillator gives an exact resonance ladder after a π/4\pi/4 contour rotation, while a PT-symmetric imaginary-linear potential in a box gives an exact Airy determinant whose two lowest zeros collide at an exceptional point.

Complex boundary data are part of the operator

Section titled “Complex boundary data are part of the operator”

Use the book’s normal form

[2 ⁣d2 ⁣dz2+V(z;μ)]ψ=Eψ,\left[ -\hbar^2\frac{\dd^2}{\dd z^2} +V(z;\mu) \right]\psi = E\psi,

and write

R0(z;E,μ)=V(z;μ)E,y2=R0(z;E,μ).R_0(z;E,\mu)=V(z;\mu)-E, \qquad y^2=R_0(z;E,\mu).

The differential expression does not yet determine a spectral problem. A complete complex boundary passport contains at least

DatumWhat must be declared
Spatial contourAn oriented contour Γ\Gamma on the base, including its homotopy class relative to singularities and cuts
Endpoint dataFinite boundary lines, or asymptotic sectors and a chosen subdominant or outgoing branch at each end
Spectral coverA branch of y=VEy=\sqrt{V-E} along each lifted segment and the sheet changes across cuts
Semiclassical phasearg\arg\hbar and the Borel summation direction used for the WKB series
Stokes chamberThe graph and lateral prescription used to transport canonical solutions
NormalizationBase points, Wronskians, pole factors, and any regularization at infinity
Time conventionFor resonances, the sign in the time factor, here eiEt/\ee^{-\ii Et/\hbar}

Two contours can represent the same spectral problem when they can be deformed into one another through an analytic domain while their ends remain in the same asymptotic sectors and their boundary lines are continued with the deformation. Moving an end across a sector boundary, crossing a pole, or changing sheets can change the problem even if the formula for VV is untouched.

This is the complex analogue of the domain of an unbounded operator. Writing only H=2z2+VH=-\hbar^2\partial_z^2+V suppresses the data that decide which spectrum is being discussed.

The adjective complex also labels several independent choices:

SituationWhat is complexMeaning of a determinant zero
Complex turning pointsZeros of V(z)EV(z)-EGeometry only; no spectrum is defined yet
Complex-contour problemThe contour and possibly the coefficientsEigenvalue of that declared contour domain
Resonance problemThe energy sheet and outgoing boundary linesCommon outgoing mode; a pole only under a continuation theorem
Complex-scaled problemThe rotated operator coefficientsResonance under complex-scaling hypotheses
PT-symmetric problemA generally nonselfadjoint domainA real zero or one member of a conjugate pair

None of the rows implies another. In particular, a real self-adjoint problem routinely has complex turning points, and a non-Hermitian problem can have real eigenvalues.

Branch language is safe only when the branched object is named. A complex spectral calculation may use all of the following at once:

  • the two-sheeted spatial WKB cover y2=V(z)Ey^2=V(z)-E;
  • the analytically continued Borel surface of a formal WKB series;
  • the energy or momentum surface of the continued resolvent, such as the two choices in E=2k2E=\hbar^2k^2; and
  • a ramified spatial cover created by a multivalued potential or a logarithmic endpoint phase.

A deck transformation of yy is not automatically a change of resolvent sheet. Crossing a Borel cut is not automatically a spatial contour deformation. Every phrase such as “second sheet” should name which cover it refers to.

Infinity divides the plane into decay wedges

Section titled “Infinity divides the plane into decay wedges”

Suppose that along the relevant directions

V(z;μ)=azm(1+o(1)),a0,V(z;\mu) = a z^m\left(1+o(1)\right), \qquad a\neq0,

with m>0m>0. Away from turning points, the leading exponent is

zV(ζ)E ⁣dζ2am+2z(m+2)/2,ψ±(z)zm/4exp[±2a(m+2)z(m+2)/2].\begin{aligned} \int^z\sqrt{V(\zeta)-E}\,\dd\zeta &\sim \frac{2\sqrt a}{m+2} z^{(m+2)/2}, \\ \psi_\pm(z) &\sim z^{-m/4} \exp\left[ \pm \frac{2\sqrt a}{(m+2)\hbar} z^{(m+2)/2} \right]. \end{aligned}

Let z=reiϕz=r\ee^{\ii\phi} and =eiϑ\hbar=|\hbar|\ee^{\ii\vartheta}. The sector boundaries obey

Re[az(m+2)/2]=0.\operatorname{Re} \left[ \frac{\sqrt a}{\hbar} z^{(m+2)/2} \right] =0.

Adjacent boundaries differ by 2π/(m+2)2\pi/(m+2). Inside each intervening sector exactly one leading branch is subdominant, except on a boundary where the two branches have equal exponential magnitude. A polynomial problem therefore asks for decay in a pair of sectors, not merely at the symbols ++\infty and -\infty.

For a polynomial coefficient, classical global ODE theory constructs a canonical subdominant solution in each noncritical sector, unique up to normalization. Continuing those solutions from sector to sector produces Stokes multipliers. Their Wronskians are therefore natural spectral determinants. The construction survives beyond polynomials, but singular endpoints, logarithmic phases, and long-range scattering require their own asymptotic normalization.

Three exceptional sets must not be conflated

Section titled “Three exceptional sets must not be conflated”

As parameters move, three geometrically different events can occur.

Turning points collide when

R0(z;E,μ)=0,zR0(z;E,μ)=0.R_0(z;E,\mu)=0, \qquad \partial_zR_0(z;E,\mu)=0.

Equivalently, the discriminant of R0R_0 with respect to zz vanishes. The local Airy model then fails and is replaced by a higher turning-point model, often of Weber type for a generic pair collision.

For a relevant lifted cycle or saddle connection γ\gamma, a graph wall occurs when

Im[eiθZγ(E,μ)]=0,Zγ=γy ⁣dz,\operatorname{Im} \left[ \ee^{-\ii\theta} Z_\gamma(E,\mu) \right] =0, \qquad Z_\gamma = \int_\gamma y\,\dd z,

together with the trajectory condition that realizes the corresponding finite Stokes curve. The spectral curve can remain smooth across this wall. Voros coordinates jump, but a correctly transported exact determinant remains covariant.

The boundary determinant has a multiple zero

Section titled “The boundary determinant has a multiple zero”

A second-order spectral exceptional point satisfies

D(Ec,μc)=0,ED(Ec,μc)=0.D(E_c,\mu_c)=0, \qquad \partial_ED(E_c,\mu_c)=0.

It is a degeneracy of the global boundary problem. It need not coincide with a collision of turning points, and a Stokes wall by itself need not make any eigenvalue multiple.

SetDefined byObject that degenerates
Curve discriminantR0=zR0=0R_0=\partial_zR_0=0The spectral cover
Stokes wallA phased period plus a finite-trajectory conditionThe chamber description
Exceptional pointD=ED=0D=\partial_ED=0The boundary-value spectrum

Keeping these sets separate is especially important in numerical work. A root finder can cross a Stokes wall without losing the eigenvalue, and an exceptional point can occur while every turning point remains simple.

For scattering problems there is a fourth critical locus: a threshold where a uniformizing coordinate such as E=2k2E=\hbar^2k^2 ramifies. The continued resolvent may be meromorphic in kk but not in EE, or may need logarithmic sheets in long-range and even-dimensional settings. A threshold is neither a determinant double zero nor a turning-point collision.

Relative cycles organize complex connection data

Section titled “Relative cycles organize complex connection data”

Let SjS_j and SkS_k be the chosen endpoint sectors. After fixing normalizations, let Ψj\Psi_j be subdominant in SjS_j and Ψk\Psi_k subdominant in SkS_k. Because the equation has no first-derivative term,

Djk(E,)=Wz[Ψj,Ψk]D_{jk}(E,\hbar) = W_z[\Psi_j,\Psi_k]

is independent of zz. Its vanishing says that a single nonzero solution satisfies both endpoint conditions.

The connecting paths now live naturally in relative homology: their boundaries may lie above the two ends of Γ\Gamma, while closed cycles measure monodromy around cuts and turning points. A change of basis gives

Ψ~j=fj(E,)Ψj,Ψ~k=fk(E,)Ψk,\widetilde\Psi_j=f_j(E,\hbar)\Psi_j, \qquad \widetilde\Psi_k=f_k(E,\hbar)\Psi_k,

and hence

D~jk=fjfkDjk.\widetilde D_{jk} = f_jf_kD_{jk}.

Nonvanishing factors change the determinant normalization but not its zero set. They do matter for derivatives, residues, zeta-regularized identifications, and any comparison of absolute connection amplitudes.

In a fixed exact-WKB chamber, transport decomposes DjkD_{jk} into Borel sums of open-path and closed-cycle Voros symbols. Schematically,

Djk=Fjk(SθXβ1,,SθXγ1,),D_{jk} = F_{jk} \left( \mathcal S_\theta X_{\beta_1}, \ldots, \mathcal S_\theta X_{\gamma_1}, \ldots \right),

where the precise Laurent polynomial or convergent expression depends on the graph and endpoint normalization. Across a wall the coordinates and the expression for FjkF_{jk} both change so that the transported determinant describes the same boundary problem.

Outgoing conditions define resonance sheets

Section titled “Outgoing conditions define resonance sheets”

Assume for the moment a short-range real potential on the real line. With the time convention

Ψ(x,t)=eiEt/ψ(x),\Psi(x,t)=\ee^{-\ii Et/\hbar}\psi(x),

a resonance energy is usually written

E=ERiΓ2,Γ>0.E_*=E_R-\frac{\ii\Gamma}{2}, \qquad \Gamma>0.

Its time dependence decays as

Ψ(x,t)eΓt/(2).|\Psi(x,t)| \propto \ee^{-\Gamma t/(2\hbar)}.

If k(E)=E/k(E)=\sqrt E/\hbar is normalized on the outgoing sheet, the Siegert conditions are

ψ(x)C+e+ikx,x+,ψ(x)Ceikx,x.\begin{aligned} \psi(x) &\sim C_+\ee^{+\ii kx}, &&x\to+\infty, \\ \psi(x) &\sim C_-\ee^{-\ii kx}, &&x\to-\infty. \end{aligned}

For Imk<0\operatorname{Im}k<0, these waves grow exponentially in space on the real axis. That is not a contradiction: a Gamow state is not an L2(R)L^2(\mathbb R) eigenfunction. Under appropriate scattering hypotheses, the same EE_* appears as a pole of the meromorphically continued resolvent or scattering matrix.

Let f+f_+ and ff_- be the right- and left-outgoing Jost solutions. Their resonance determinant is

Dout(E)=W[f,f+].D_{\mathrm{out}}(E) = W[f_-,f_+].

Incoming solutions define the time-reversed, or anti-resonance, sheet. Changing the sign of the time convention reverses which half-plane is called decaying; this sign must be part of every resonance calculation.

The implication

Dout(E)=0a common outgoing solution existsD_{\mathrm{out}}(E)=0 \quad\Longleftrightarrow\quad \text{a common outgoing solution exists}

is a linear-ODE statement. Promoting that zero to a pole of a continued resolvent additionally requires a meromorphic continuation on specified source and target spaces, a Green-kernel or Fredholm representation, control of thresholds, and exclusion of cancellation by the numerator. This operator-theory step must be cited rather than hidden inside the word resonance.

A metastable well acquires an exponentially small width

Section titled “A metastable well acquires an exponentially small width”

The cubic prototype

Vg(x)=x22gx3,g>0,V_g(x) = \frac{x^2}{2}-gx^3, \qquad g>0,

has a local well and a barrier of height 1/(54g2)1/(54g^2). For a reference energy below that height, let a<b<ca<b<c be the three real turning points and define

J(E)=2abEVg(x) ⁣dx,K(E)=bcVg(x)E ⁣dx.\begin{aligned} J(E) &= 2\int_a^b \sqrt{E-V_g(x)}\,\dd x, \\ K(E) &= \int_b^c \sqrt{V_g(x)-E}\,\dd x. \end{aligned}

At the actual complex resonance, the turning points and cycles are the analytic continuations of this reference configuration. Suppose an audited outgoing connection word gives

Qout=Qwell+icoutYesc+O(Yesc2),\mathcal Q_{\mathrm{out}} = \mathcal Q_{\mathrm{well}} +\ii c_{\mathrm{out}}Y_{\mathrm{esc}} +O(Y_{\mathrm{esc}}^2),

where cout>0c_{\mathrm{out}}>0 in the declared convention and

Yescexp(2K).Y_{\mathrm{esc}} \sim \exp\left(-\frac{2K}{\hbar}\right).

If E0E_0 is a simple real zero of Qwell\mathcal Q_{\mathrm{well}}, implicit solution gives

δE=icout(E0,)Yesc(E0,)EQwell(E0,)+O(Yesc2).\delta E = -\ii \frac{ c_{\mathrm{out}}(E_0,\hbar) Y_{\mathrm{esc}}(E_0,\hbar) }{ \partial_E\mathcal Q_{\mathrm{well}}(E_0,\hbar) } +O(Y_{\mathrm{esc}}^2).

When the denominator is positive, the retarded boundary condition puts the pole below the real axis. At leading semiclassical order its scale is

ΓT(E0)exp[2K(E0)],T(E)=EJ(E),\Gamma \asymp \frac{\hbar}{T(E_0)} \exp\left[-\frac{2K(E_0)}{\hbar}\right], \qquad T(E)=\partial_EJ(E),

up to the connection-dependent prefactor. The exponential scale follows from barrier transport; the sign and prefactor follow from the complete outgoing connection word. Neither should be guessed from KK alone.

Complex scaling converts outgoing growth into decay

Section titled “Complex scaling converts outgoing growth into decay”

Rotate the coordinate by

z=eiαx,0<α<π2.z=\ee^{\ii\alpha}x, \qquad 0<\alpha<\frac{\pi}{2}.

The differential expression becomes

Hα=e2iα2 ⁣d2 ⁣dx2+V(eiαx).H_\alpha = -\ee^{-2\ii\alpha}\hbar^2\frac{\dd^2}{\dd x^2} +V(\ee^{\ii\alpha}x).

For a possibly complex resonance momentum,

eikeiαx=exp[xIm(keiα)].\left| \ee^{\ii k\ee^{\ii\alpha}x} \right| = \exp\left[ -x\operatorname{Im} \left(k\ee^{\ii\alpha}\right) \right].

Thus right-end decay requires Im(keiα)>0\operatorname{Im}(k\ee^{\ii\alpha})>0. For real kk, this reduces to the familiar split exp(ikxcosαkxsinα)\exp(\ii kx\cos\alpha-kx\sin\alpha). In dilation-analytic settings, the continuous spectrum rotates by e2iα\ee^{-2\ii\alpha}, bound-state eigenvalues stay fixed, and resonance poles uncovered between the original and rotated continua appear as discrete eigenvalues independent of α\alpha over an allowed interval.

The useful numerical diagnostic is therefore rotation stationarity: a true exposed resonance remains nearly fixed as α\alpha and the basis size vary, whereas discretized continuum points rotate.

An exact resonance laboratory: the inverted oscillator

Section titled “An exact resonance laboratory: the inverted oscillator”

Consider

Hinv=2 ⁣d2 ⁣dz2z2H_{\mathrm{inv}} = -\hbar^2\frac{\dd^2}{\dd z^2}-z^2

with outgoing behavior on both real ends. Set

z=eiπ/4x.z=\ee^{\ii\pi/4}x.

Then

Hinv=eiπ/22 ⁣d2 ⁣dx2eiπ/2x2=i(2 ⁣d2 ⁣dx2+x2).\begin{aligned} H_{\mathrm{inv}} &= -\ee^{-\ii\pi/2}\hbar^2\frac{\dd^2}{\dd x^2} -\ee^{\ii\pi/2}x^2 \\ &= -\ii \left( -\hbar^2\frac{\dd^2}{\dd x^2}+x^2 \right). \end{aligned}

The rotated boundary condition is ordinary Gaussian decay. Since the oscillator in parentheses has eigenvalues (2n+1)\hbar(2n+1),

Enres=i(2n+1),n=0,1,2,.E_n^{\mathrm{res}} = -\ii\hbar(2n+1), \qquad n=0,1,2,\ldots.

The corresponding entire functions are

ψn(z)=Hn(eiπ/4z)exp(iz22),\psi_n(z) = H_n\left( \frac{\ee^{-\ii\pi/4}z}{\sqrt\hbar} \right) \exp\left( \frac{\ii z^2}{2\hbar} \right),

where HnH_n is a Hermite polynomial. On the positive real axis the phase has local momentum p=z>0p=z>0; on the negative real axis it has p=z<0p=z<0. It is therefore outgoing at both ends even though its modulus does not decay there.

The turning points solve

Enres+z2=0E_n^{\mathrm{res}}+z^2=0

and lie on the rotated contour. Put E=iεE=-\ii\varepsilon and z=eiπ/4xz=\ee^{\ii\pi/4}x. Between the turning points,

E+z2 ⁣dz=εx2 ⁣dx.\sqrt{E+z^2}\,\dd z = \sqrt{\varepsilon-x^2}\,\dd x.

Thus the closed classical action is

p ⁣dz=2εεεx2 ⁣dx=πε.\begin{aligned} \oint p\,\dd z &= 2\int_{-\sqrt\varepsilon}^{\sqrt\varepsilon} \sqrt{\varepsilon-x^2}\,\dd x \\ &= \pi\varepsilon. \end{aligned}

The oscillator condition p ⁣dz=2π(n+12)\oint p\dd z=2\pi\hbar(n+\tfrac12) gives precisely ε=(2n+1)\varepsilon=\hbar(2n+1). For this quadratic model the leading action plus the turning-point index is exact. Generic barrier tops have higher WKB corrections and may require a uniform Weber normal form.

The opposite rotation gives

Enanti=+i(2n+1),E_n^{\mathrm{anti}} = +\ii\hbar(2n+1),

the time-reversed anti-resonance ladder. The differential expression is the same; the endpoint sectors are not.

The exact parabolic-cylinder determinants make that last distinction especially sharp. Up to zero-free normalizations, one may choose

Δout(E)=1Γ(12iE2),Δin(E)=1Γ(12+iE2).\begin{aligned} \Delta_{\mathrm{out}}(E) &= \frac{1}{ \Gamma\left( \frac12-\frac{\ii E}{2\hbar} \right)}, \\ \Delta_{\mathrm{in}}(E) &= \frac{1}{ \Gamma\left( \frac12+\frac{\ii E}{2\hbar} \right)}. \end{aligned}

Their zeros are the lower and upper ladders respectively. Euler’s reflection identity gives

1+exp(πE)=2πexp(πE2)×Δout(E)Δin(E).\begin{aligned} 1+\exp\left(-\frac{\pi E}{\hbar}\right) ={}& 2\pi \exp\left(-\frac{\pi E}{2\hbar}\right) \\ &\times \Delta_{\mathrm{out}}(E) \Delta_{\mathrm{in}}(E). \end{aligned}

The bare closed-cycle equation on the left contains both ladders. Only the open boundary determinant selects outgoing resonances rather than incoming anti-resonances.

This quadratic example uses an exact analytic contour deformation. It is not literally an application of the short-range Aguilar–Balslev–Combes theorem: the inverted potential is neither short-range nor bounded below.

A complex-scaled inverted-oscillator contour beside the three stages of a PT-symmetric exceptional-point collision.

Complex boundary geometry selects the spectral sheet. Left: the outgoing inverted-oscillator solution on the real axis becomes Gaussian-decaying on the rotated contour z=eiπ/4xz=\ee^{\ii\pi/4}x, with its two turning points on that contour. Right: two real zeros of a PT-symmetric determinant merge at D=ED=0D=\partial_ED=0 and continue as a conjugate pair. A contour rotation, a Stokes wall, and a determinant double zero are distinct operations.

PT symmetry constrains the zero set, not every zero

Section titled “PT symmetry constrains the zero set, not every zero”

On a parity-symmetric contour, define

(PTψ)(z)=ψ(z).(\mathcal P\mathcal T\psi)(z) = \psi^*(-z^*).

The differential expression is PT symmetric when

V(z;μ)=V(z;μ)V(-z^*;\mu)=V(z;\mu)^*

for real values of the declared couplings. The domain must also be invariant: parity and conjugation must exchange the two endpoint sectors or finite boundary lines.

If

Hψ=Eψ,H\psi=E\psi,

then anti-linearity gives

H(PTψ)=E(PTψ).H(\mathcal P\mathcal T\psi) = E^*(\mathcal P\mathcal T\psi).

There are two possibilities.

  • If a simple eigenfunction is also a PT eigenstate, then its eigenvalue is real. After a phase choice one can write PTψ=ψ\mathcal P\mathcal T\psi=\psi.

  • If PT maps the eigenfunction to a linearly independent state, then EE and EE^* form a pair. The symmetry is often called broken on that pair.

PT symmetry therefore supplies a conjugation law for the determinant. With a suitable normalization it can be written

D(E;μ)=D(E;μ),D(E^*;\mu)^*=D(E;\mu),

or the same equation multiplied by a nonzero analytic factor. It does not prove positivity, completeness, diagonalizability, or the existence of a positive metric. Those are separate spectral questions.

For polynomial problems at infinity, the domain condition is easy to miss. A potential may satisfy the pointwise PT relation while a chosen pair of decay wedges does not map into itself. That contour problem is not PT symmetric.

Exceptional points are determinant double zeros

Section titled “Exceptional points are determinant double zeros”

Let D(E,g)D(E,g) be analytic near a real point (Ec,gc)(E_c,g_c) and suppose

D(Ec,gc)=0,DE(Ec,gc)=0,DEE(Ec,gc)0,Dg(Ec,gc)0.\begin{aligned} D(E_c,g_c)&=0, & D_E(E_c,g_c)&=0, \\ D_{EE}(E_c,g_c)&\neq0, & D_g(E_c,g_c)&\neq0. \end{aligned}

Taylor expansion gives

0=Dgδg+12DEEδE2+DEgδEδg+O(δE3,δg2),0 = D_g\,\delta g +\frac12D_{EE}\,\delta E^2 +D_{Eg}\,\delta E\,\delta g +O\left(\delta E^3,\delta g^2\right),

where all displayed derivatives are evaluated at the critical point. Consequently,

δE2=2DgDEEδg+O(δg3/2).\delta E^2 = -\frac{2D_g}{D_{EE}}\delta g +O\left(\delta g^{3/2}\right).

The two branches have a square-root Puiseux expansion. For a PT-symmetric one-parameter family, the coefficient can have the sign that produces two real roots on one side and a complex-conjugate pair on the other.

The equations D=DE=0D=D_E=0 detect an algebraic double zero. To call the point an exceptional point in the operator-theoretic sense, one also checks that the geometric multiplicity drops to one. In a scalar second-order problem with two separated boundary lines this is the generic outcome, but an ordinary semisimple degeneracy in a larger system must not be mislabeled.

The determinant is badly conditioned near the double zero because DED_E vanishes. Newton iteration in EE alone loses its usual quadratic model. Solve the augmented system

D(E,g)=0,DE(E,g)=0D(E,g)=0, \qquad D_E(E,g)=0

for (E,g)(E,g), or track both branches with a Puiseux parameter.

Set =1\hbar=1 and consider

Hgψ=ψ+igxψ=Eψ,ψ(1)=ψ(1)=0,g>0.\begin{aligned} H_g\psi &= -\psi''+\ii g x\psi = E\psi, \\ \psi(-1)&=\psi(1)=0, \qquad g>0. \end{aligned}

The potential is not real, but V(x)=V(x)V(-x)^*=V(x) and the Dirichlet domain is PT invariant. Define the principal cube root

α=(ig)1/3=g1/3eiπ/6\alpha=(\ii g)^{1/3} = g^{1/3}\ee^{\ii\pi/6}

and the Airy coordinate

z(x;E,g)=α(x+iEg).z(x;E,g) = \alpha \left( x+\frac{\ii E}{g} \right).

Because α3=ig\alpha^3=\ii g,

 ⁣d2 ⁣dx2Ai(z)=(igxE)Ai(z),\frac{\dd^2}{\dd x^2} \operatorname{Ai}(z) = (\ii gx-E)\operatorname{Ai}(z),

and similarly for Bi\operatorname{Bi}. Put

z±=α(±1+iEg).z_\pm = \alpha \left( \pm1+\frac{\ii E}{g} \right).

The two endpoint equations have a nonzero common coefficient vector precisely when

DA(E,g):=Ai(z)Bi(z+)Ai(z+)Bi(z)=0.\begin{aligned} D_{\mathrm A}(E,g) :={}& \operatorname{Ai}(z_-) \operatorname{Bi}(z_+) \\ &- \operatorname{Ai}(z_+) \operatorname{Bi}(z_-) =0. \end{aligned}

For g>0g>0 and the declared cube-root branch,

ΔA(E,g):=eiπ/6DA(E,g)\Delta_{\mathrm A}(E,g) := \ee^{-\ii\pi/6}D_{\mathrm A}(E,g)

is real when EE is real. Multiplying by this phase changes neither its zeros nor the ratio 2Dg/DEE-2D_g/D_{EE}.

At g=10g=10, the first two roots are

E0=4.5784904182916919,E1=8.9966832557123482.\begin{aligned} E_0&=4.5784904182916919\ldots, \\ E_1&=8.9966832557123482\ldots. \end{aligned}

They approach one another as gg grows. Solving the augmented Airy system gives the first collision

gc=12.3124556722605251,Ec=7.1085995967649488,ΔA(Ec,gc)=EΔA(Ec,gc)=0.\begin{aligned} g_c &= 12.3124556722605251\ldots, \\ E_c &= 7.1085995967649488\ldots, \\ \Delta_{\mathrm A}(E_c,g_c) &= \partial_E\Delta_{\mathrm A}(E_c,g_c) =0. \end{aligned}

Numerically, Ec/gc=1/3E_c/g_c=1/\sqrt3 to the working precision. Direct differentiation of the determinant gives

2ΔgΔEE=2.3880593762328621.-\frac{2\Delta_g}{\Delta_{EE}} = -2.3880593762328621\ldots.

Hence the local branches have the leading form

E±(g)=Ec±1.5453347133332837gcg+O(gcg)E_\pm(g) = E_c \pm 1.5453347133332837\ldots \sqrt{g_c-g} +O(g_c-g)

below the collision. Above it, the square root is imaginary and the pair leaves the real axis. For example, at g=13g=13,

E±=7.2169577471438905±1.3047650935833622i.E_\pm = 7.2169577471438905\ldots \pm 1.3047650935833622\ldots\ii.

The only turning point is

xt=iEg.x_t=-\frac{\ii E}{g}.

It remains simple at (Ec,gc)(E_c,g_c). The exceptional point is therefore a global double zero of the endpoint determinant, not a turning-point collision. This is the promised concrete separation of two exceptional sets.

At fixed gg, high eigenvalues satisfy

Enn2π24,n,E_n \sim \frac{n^2\pi^2}{4}, \qquad n\to\infty,

because the kinetic term dominates on the finite interval. A finite difference matrix provides an independent check of the Airy determinant: below gcg_c its lowest pair is real, while above gcg_c the discretized matrix produces the same conjugate pair.

Conjugate actions make large order oscillate

Section titled “Conjugate actions make large order oscillate”

Page 7 used a single positive action to produce a nearly fixed-sign factorial-over-power tail. Complex boundary problems often place the nearest Borel singularities at a conjugate pair

A=Aeiϕ,A=Aeiϕ.A=|A|\ee^{\ii\phi}, \qquad A^*=|A|\ee^{-\ii\phi}.

If their Stokes-weighted leading amplitudes are CC and CC^*, their combined contribution has the form

anCΓ(n+β)An+β+CΓ(n+β)(A)n+β=2CΓ(n+β)An+βcos[argC(n+β)ϕ].\begin{aligned} a_n &\sim C\frac{\Gamma(n+\beta)}{A^{n+\beta}} + C^*\frac{\Gamma(n+\beta)}{(A^*)^{n+\beta}} \\ &= \frac{2|C|\Gamma(n+\beta)}{|A|^{n+\beta}} \cos\left[ \arg C-(n+\beta)\phi \right]. \end{aligned}

The envelope still reveals A|A|, but the coefficients oscillate and a plain ratio an/an1a_n/a_{n-1} need not converge. Phase-aware fits, Borel singularity plots, or short recurrences are better diagnostics. Whether both conjugate sectors enter with conjugate weights depends on the boundary problem and summation prescription; the potential alone does not decide it.

How complex turning points enter a practical WKB calculation

Section titled “How complex turning points enter a practical WKB calculation”

For a finite-interval PT problem, a straight endpoint path can miss the exponentially small term responsible for the interesting spectral structure. A leading one-turning-point calculation illustrates the mechanism. Let xtx_t be the relevant complex turning point and define, in a convention with oscillatory momentum p=EVp=\sqrt{E-V},

I+=xt1p(x) ⁣dx.I_+ = \int_{x_t}^{1}p(x)\,\dd x.

PT symmetry relates the left integral to I+I_+^*. In the elementary Airy matching convention used by Bender and Jones, the leading secular equation takes the form

sin(2ReI+)+12exp(2ImI+)=0.\sin\left(2\operatorname{Re}I_+\right) + \frac12 \exp\left(2\operatorname{Im}I_+\right) =0.

The exponential term is invisible to a direct no-turning-point rule. When it is small, the spectrum resembles the ordinary box. When it becomes comparable with the sine term, real roots can merge; after it is too large to balance a real sine, continuation to complex EE is required.

This equation is a leading WKB diagnostic, not the exact Airy determinant above and not a universal formula. For a pair of relevant turning points the matching equation changes. In exact WKB, the upgrade requires resummed open-path and cycle Voros symbols, the correct local connection matrices, and the chamber covariance of Page 5.

  1. Declare the domain. Record the spatial contour, endpoint sectors or finite boundary lines, time convention, and sheet of every asymptotic momentum.

  2. Locate all turning points and singularities. Continue them as functions of EE and the couplings; do not select only the roots near the real axis by habit.

  3. Draw the phased graph. Fix the Borel direction and determine which turning points actually connect the endpoint regions in the chosen chamber.

  4. Choose relative paths and cycles. Record orientations, intersections, branch cuts, and any pole regularization.

  5. Build boundary solutions. Use exact special functions where available; otherwise use Borel-summed WKB, numerical integration, or a controlled uniform approximation.

  6. Form a determinant. Prefer a Wronskian or exterior product whose zeros are invariant under nonzero rescalings of the boundary solutions.

  7. Search the correct sheet. For resonances, continue the outgoing momentum and compare with complex scaling or a scattering pole. For a PT problem, track conjugate branches together.

  8. Classify singular events. Test separately for a curve discriminant, a Stokes wall, and D=DE=0D=D_E=0.

  9. Demand independent checks. Vary base points, precision, contour angle, and discretization. A resonance should be stationary under an allowed scaling-angle change; an exceptional point should satisfy the augmented determinant system.

The companion checker instantiates every formula on this page. It performs the following independent tests:

  • verifies the polynomial wedge spacing from the leading exponent;
  • checks the inverted-oscillator contour rotation and Hermite residuals;
  • compares a finite-difference complex-scaled oscillator with En=i(2n+1)E_n=-\ii(2n+1);
  • evaluates the Airy determinant and its PT reality phase at high precision;
  • solves ΔA=EΔA=0\Delta_{\mathrm A}=\partial_E\Delta_{\mathrm A}=0 for the first exceptional point;
  • checks the predicted square-root coefficient on both sides of the collision;
  • compares Airy roots with an unrelated finite-difference matrix; and
  • confirms conjugate pairing above the exceptional point.

The script reports its numerical tolerances and limitations. It does not prove dilation analyticity, Borel summability, completeness of resonant states, or the absence of additional spectral sheets.

Treating a complex contour as a plotting choice. The endpoint sectors and their subdominant lines define the operator domain. Crossing a sector boundary can replace a bound-state problem by a different non-Hermitian problem.

Calling every nonreal eigenvalue a resonance. A resonance is tied to an outgoing analytic continuation of a scattering problem. A complex eigenvalue of a finite PT-symmetric box is a genuine eigenvalue of that nonselfadjoint domain, not automatically a scattering pole.

Assuming PT symmetry implies reality. It implies that the spectral set is closed under complex conjugation when the domain is invariant. Reality requires an unbroken eigenstate or a stronger theorem.

Equating an exceptional point with coalescing turning points. The former is a multiple zero of a global determinant; the latter is a singularity of the local spectral curve. The Airy box has an exceptional point while its sole turning point stays simple.

Using complex scaling outside its analytic class. A stable-looking eigenvalue from one rotation angle is not enough. Check analyticity or use an admissible distortion, and test angle stationarity.

Forgetting the time sign. With eiEt/\ee^{-\ii Et/\hbar}, decaying resonances lie in the lower half of the energy plane. Reversing the time factor reverses the naming of resonance and anti-resonance sheets.

Applying a real-axis WKB integral to a multivalued potential. The turning points and endpoints may lie on different sheets. A path that crosses a branch cut without recording the sheet change does not define the claimed action.

For V(z)azmV(z)\sim az^m, derive the boundary rays on which the two leading WKB exponentials have equal magnitude. Show that there are m+2m+2 canonical sectors modulo 2π2\pi.

Solution

Write

χ(ϕ)=argaarg+m+22ϕ.\chi(\phi) = \arg\sqrt a-\arg\hbar +\frac{m+2}{2}\phi.

Equal magnitude means cosχ=0\cos\chi=0, so

ϕk=2m+2[(k+12)πarga+arg].\phi_k = \frac{2}{m+2} \left[ \left(k+\frac12\right)\pi -\arg\sqrt a +\arg\hbar \right].

Adjacent rays are separated by 2π/(m+2)2\pi/(m+2). There are therefore m+2m+2 sectors in one full turn. The subdominant sign alternates from sector to sector.

Apply z=eiπ/4xz=\ee^{\ii\pi/4}x to Hinv=2z2z2H_{\mathrm{inv}}=-\hbar^2\partial_z^2-z^2. Derive the resonance energies and verify that the analytically continued Gaussian is outgoing on both real ends.

Solution

The derivative and potential acquire the phases

2z2=eiπ/22x2,z2=eiπ/2x2.-\hbar^2\partial_z^2 = -\ee^{-\ii\pi/2}\hbar^2\partial_x^2, \qquad -z^2=-\ee^{\ii\pi/2}x^2.

Thus Hinv=iHoscH_{\mathrm{inv}}=-\ii H_{\mathrm{osc}}, and

En=i(2n+1).E_n=-\ii\hbar(2n+1).

The rotated Gaussian becomes exp(iz2/(2))\exp(\ii z^2/(2\hbar)). Its phase derivative is p=zp=z: momentum points right for z>0z>0 and left for z<0z<0, which is outgoing at both ends.

If the endpoint solutions are rescaled by nonzero analytic factors fjf_j and fkf_k, show that the spectral zero divisor is unchanged. What quantity relevant to residues does change?

Solution

Bilinearity of the Wronskian gives

D~jk=W[fjΨj,fkΨk]=fjfkDjk,\widetilde D_{jk} = W[f_j\Psi_j,f_k\Psi_k] = f_jf_kD_{jk},

because fjf_j and fkf_k depend on spectral parameters, not on zz. Their product is nonzero, so the zeros and their multiplicities are unchanged. At a simple zero EE_*,

D~(E)=fj(E)fk(E)D(E),\widetilde D'(E_*) = f_j(E_*)f_k(E_*)D'(E_*),

so a residue proportional to 1/D(E)1/D'(E_*) changes unless the numerator and normalization are transformed consistently.

Assume the potential and domain obey the PT conditions on this page. Show that a spectral point is either real or belongs to a conjugate pair. Why is a simple PT-invariant state real?

Solution

From Hψ=EψH\psi=E\psi and anti-linearity,

H(PTψ)=E(PTψ).H(\mathcal P\mathcal T\psi) = E^*(\mathcal P\mathcal T\psi).

The transformed function obeys the same endpoint conditions, so EE^* is also spectral. If the eigenspace is one-dimensional and invariant, PTψ=cψ\mathcal P\mathcal T\psi=c\psi for some nonzero cc. Comparing the two eigenvalue equations gives E=EE=E^*, hence EE is real.

5. Derive the exceptional-point square root

Section titled “5. Derive the exceptional-point square root”

Starting from a double zero with DEEDg0D_{EE}D_g\neq0, derive the leading two spectral branches. State why this calculation alone does not prove the existence of a Jordan block.

Solution

Taylor expansion gives

Dgδg+12DEEδE2+O(δEδg,δE3,δg2)=0.D_g\delta g +\frac12D_{EE}\delta E^2 +O(\delta E\delta g,\delta E^3,\delta g^2) =0.

Since δE=O(δg1/2)\delta E=O(\delta g^{1/2}),

E±(g)=Ec±2DgDEE(ggc)+O(ggc).E_\pm(g) = E_c \pm \sqrt{-\frac{2D_g}{D_{EE}}(g-g_c)} +O(g-g_c).

This describes the zero divisor of an analytic scalar function. A Jordan claim additionally concerns the geometric multiplicity and the domain of the operator pencil; those data are not contained in the Taylor series alone.

Starting from ψ+igxψ=Eψ-\psi''+\ii gx\psi=E\psi, verify the Airy coordinate and derive DAD_{\mathrm A} from the two Dirichlet equations.

Solution

Let z=α(x+iE/g)z=\alpha(x+\ii E/g) with α3=ig\alpha^3=\ii g. For an Airy solution uzz=zuu_{zz}=zu,

uxx=α2zu=α3(x+iEg)u=(igxE)u.u_{xx} = \alpha^2zu = \alpha^3 \left(x+\frac{\ii E}{g}\right)u = (\ii gx-E)u.

Hence

ψ=AAi(z)+BBi(z).\psi=A\operatorname{Ai}(z)+B\operatorname{Bi}(z).

The two endpoint equations form the matrix

(Ai(z)Bi(z)Ai(z+)Bi(z+))(AB)=0.\begin{pmatrix} \operatorname{Ai}(z_-)&\operatorname{Bi}(z_-) \\ \operatorname{Ai}(z_+)&\operatorname{Bi}(z_+) \end{pmatrix} \begin{pmatrix}A\\B\end{pmatrix} =0.

Its determinant is exactly DAD_{\mathrm A}.

Suppose

Qwell(E)+icY=0,\mathcal Q_{\mathrm{well}}(E) +\ii cY=0,

where c>0c>0, Y>0Y>0, and Qwell(E0)>0\mathcal Q_{\mathrm{well}}'(E_0)>0. Find the leading displacement of the simple real root E0E_0 and the sign of the width for eiEt/\ee^{-\ii Et/\hbar}.

Solution

Set E=E0+δEE=E_0+\delta E and linearize:

Qwell(E0)δE+icY=0.\mathcal Q_{\mathrm{well}}'(E_0)\delta E +\ii cY=0.

Therefore

δE=icYQwell(E0).\delta E = -\ii \frac{cY}{\mathcal Q_{\mathrm{well}}'(E_0)}.

Writing E=ERiΓ/2E=E_R-\ii\Gamma/2 gives

Γ=2cYQwell(E0)>0.\Gamma = \frac{2cY}{\mathcal Q_{\mathrm{well}}'(E_0)}>0.

The state decays in time. Reversing the radiation or time convention reverses the sign.

8. Sum a conjugate pair of large-order contributions

Section titled “8. Sum a conjugate pair of large-order contributions”

Starting with actions A=AeiϕA=|A|\ee^{\ii\phi} and AA^* and amplitudes C=CeiχC=|C|\ee^{\ii\chi} and CC^*, derive the oscillatory cosine law.

Solution

The first contribution is

CΓ(n+β)An+βei[χ(n+β)ϕ].\frac{|C|\Gamma(n+\beta)}{|A|^{n+\beta}} \ee^{\ii[\chi-(n+\beta)\phi]}.

The second is its complex conjugate. Their sum is

2CΓ(n+β)An+βcos[χ(n+β)ϕ].\frac{2|C|\Gamma(n+\beta)}{|A|^{n+\beta}} \cos\left[\chi-(n+\beta)\phi\right].

The cosine prevents an ordinary consecutive-coefficient ratio from approaching a single limit in general.

At the first Airy-box exceptional point, decide whether the spatial spectral curve is singular. Identify the calculation that detects the actual collision.

Solution

Here

R0(x;E,g)=igxE,xR0=ig.R_0(x;E,g)=\ii gx-E, \qquad \partial_xR_0=\ii g.

Since gc0g_c\neq0, the unique turning point is simple and the curve discriminant does not vanish. The spectral collision is instead detected by

DA(Ec,gc)=0,EDA(Ec,gc)=0.D_{\mathrm A}(E_c,g_c)=0, \qquad \partial_ED_{\mathrm A}(E_c,g_c)=0.

It is a global degeneracy of the two-endpoint boundary problem.

From analytic determinants to controlled numbers

Section titled “From analytic determinants to controlled numbers”

The output of this page is a declared analytic determinant on a declared complex sheet. Page 9 turns that object into controlled numbers. It develops Borel–Padé continuation on rotated and lateral rays, complex root tracking, argument-principle zero counts, precision escalation, and comparisons with direct Wronskian or matrix calculations.