Skip to content

Baxter Q-Functions and Bethe Roots

The first three pages constructed entire spectral functions using only ODE data. That construction does not, by itself, make them Baxter QQ-functions. A Baxter operator belongs to a declared integrable model; its scalar eigenvalue depends on a declared state; and its zeros become Bethe roots only in a declared spectral coordinate.

This page installs precisely those missing declarations for the homogeneous radial oscillator. The canonical solution at infinity is projected onto the two Frobenius lines at the origin, the resulting Wronskians are normalized at E=0E=0, and every parameter is matched to the module-vacuum, or highest-weight, QQ-eigenvalues of the Bazhanov–Lukyanov–Zamolodchikov conformal integrable model. For M>1M>1 and a nonexceptional twist, the equality is an established, model-specific ODE/IM correspondence—not a new name for an arbitrary determinant. Broader twist values require meromorphic continuation or a regularized limiting prescription.

The full TQTQ identity, transfer-matrix dictionary, fundamental quantum Wronskian, and YY-system begin on Page 5; Page 6 develops the paired Wronskians into exact-quantization conditions. Here a Bethe root means a zero of the selected normalized QQ-eigenvalue. The equations obeyed by those roots are deliberately deferred with the functional relation that produces them.

Unless a continuation is explicitly declared, this page excludes the ODE/IM exceptional set

RM={±[m1+(M+1)m2]:m1,m2Z0},\mathcal R_M = \left\{ \pm\bigl[m_1+(M+1)m_2\bigr] : m_1,m_2\in\mathbb Z_{\geq0} \right\},

so that l+1/2RMl+1/2\notin\mathcal R_M. Equivalently, 2p±(m1β2+m2)2p\ne\pm(m_1\beta^2+m_2). On this lattice, preferred Frobenius or zero-energy normalization data can degenerate, acquire logarithmic terms, or require a limiting definition.

The direct half-line construction of ψ+\psi_+ starts in l>3/2\Re l>-3/2, while its involutive companion ψ\psi_- starts in l<1/2\Re l<1/2; both are simultaneously available in the common strip. The identities below are first read there at generic ll and then continued meromorphically. For the physical regular spectrum, take real nonexceptional l>1/2l>-1/2 and impose the xl+1x^{l+1} boundary line.

An operator, an eigenvalue, and its roots are different objects

Section titled “An operator, an eigenvalue, and its roots are different objects”

In a finite integrable lattice model, a Baxter operator Q(u)\mathbf Q(u) is an operator-valued function commuting with the integrable family. Its eigenvalue on a common state S\lvert\mathcal S\rangle is a scalar function:

Q(u)S=Q(u;S)S.\mathbf Q(u)\lvert\mathcal S\rangle = Q(u;\mathcal S)\lvert\mathcal S\rangle.

Depending on the model and spectral coordinate, a finite-size QQ-eigenvalue is a polynomial or a trigonometric polynomial. Typical normalizations look like

QN(u)=Cj=1n(uuj),Q~N(u)=C~j=1nsinh(uuj).\begin{aligned} Q_N(u) &= C\prod_{j=1}^{n}(u-u_j), \\ \widetilde Q_N(u) &= \widetilde C \prod_{j=1}^{n}\sinh(u-u_j). \end{aligned}

The finite set {uj}\{u_j\} depends on the model, lattice size, twist, charge sector, and state. These are the finite-system Bethe roots.

The conformal scaling limit used here has operator functions Q±(λ)\mathbf Q_\pm(\lambda) acting in a Virasoro highest-weight module. The highest-weight vector p\lvert p\rangle—the module vacuum, not necessarily the global CFT vacuum—is a common eigenvector. After a convention-dependent monomial is stripped from the raw matrix element pQ±(λ)p\langle p\lvert\mathbf Q_\pm(\lambda)\rvert p\rangle, one obtains normalized functions A±(λ,p)A_\pm(\lambda,p) that, at fixed nonexceptional pp, are entire in λ2\lambda^2 and obey

A±(0,p)=1.A_\pm(0,p)=1.

Raw monomial conventions differ between primary sources, so the book uses only this invariantly normalized entire object. Put

s=λ2,Q±(s,p):=A±(s,p).s=\lambda^2, \qquad Q_\pm(s,p):=A_\pm(\sqrt{s},p).

Then Q±Q_\pm are single-valued entire functions of ss at fixed generic twist. Their twist dependence is different: A+A_+ is meromorphic in pp, analytic in the half-plane (2p)>β2\Re(2p)>-\beta^2, and A(λ,p)=A+(λ,p)A_-(\lambda,p)=A_+(\lambda,-p). Thus the pair is not jointly entire in (s,p)(s,p). In the semiclassical range relevant below, and away from their poles, they have infinitely many roots and genus-zero products:

Q±(s,p)=n=0(1ssn±).Q_\pm(s,p) = \prod_{n=0}^{\infty} \left(1-\frac{s}{s_n^\pm}\right).

The roots sn±s_n^\pm are not zeros of an ODE wavefunction as a function of xx, and they are not turning points of P(x)EP(x)-E. They are zeros in the integrable spectral variable ss of one state-dependent QQ-eigenvalue.

The radial ODE supplies two candidate entire functions

Section titled “The radial ODE supplies two candidate entire functions”

Let M>1M>1 be real and work first on the positive half-line, where x2Mx^{2M} is unambiguous. Complex rotations are made on the logarithmic cover fixed on Page 3. The canonical solution selected at infinity is normalized by

y(x,E,l)xM/2exp(xM+1M+1).y(x,E,l) \sim x^{-M/2} \exp\left(-\frac{x^{M+1}}{M+1}\right).

The inverse-square term does not alter this leading asymptotic. At the singular endpoint x=0x=0—a regular singular point on the chosen cover—choose the two Frobenius representatives

ψ+(x,E,l)xl+1,ψ(x,E,l)xl.\begin{aligned} \psi_+(x,E,l) &\sim x^{l+1}, \\ \psi_-(x,E,l) &\sim x^{-l}. \end{aligned}

Whenever both unit-leading representatives are defined without regularization, they give

Wr[ψ+,ψ]=(2l+1).\Wr[\psi_+,\psi_-]=-(2l+1).

The second representative may be defined by the exact involution

ψ(x,E,l):=ψ+(x,E,1l),\psi_-(x,E,l) := \psi_+(x,E,-1-l),

followed by analytic continuation in ll when necessary. Define the raw connection Wronskians

Δ(E,l):=Wr[y,ψ+](E,l),Δ+(E,l):=Wr[y,ψ](E,l).\begin{aligned} \Delta_-(E,l) &:= \Wr[y,\psi_+](E,l), \\ \Delta_+(E,l) &:= \Wr[y,\psi_-](E,l). \end{aligned}

Solving for yy in the Frobenius basis gives the normalization audit

y=ΔψΔ+ψ+2l+1.y = \frac{ \Delta_-\psi_- -\Delta_+\psi_+ }{ 2l+1 }.

Therefore

Δ(E,l)=0\Delta_-(E_*,l)=0

if and only if the solution recessive at positive infinity lies on the xl+1x^{l+1} line at the origin. For real l>1/2l>-1/2, this declares the regular radial problem. Its Friedrichs realization is self-adjoint with positive, discrete, simple eigenvalues EnregE_n^{\mathrm{reg}}.

The zero condition for Δ+\Delta_+ similarly selects the xlx^{-l} line. Whether either zero set is a physical spectrum depends on the endpoint domain, not on the existence of the Wronskian.

The endpoint domain decides which zeros are spectral

Section titled “The endpoint domain decides which zeros are spectral”

Positive infinity is limit-point. At zero, square integrability gives the complete real-ll ledger:

Range of llSquare-integrable Frobenius lines at zero
l1/2l\geq1/2only ψ+\psi_+
3/2<l<1/2-3/2<l<1/2, l1/2l\ne-1/2both ψ+\psi_+ and ψ\psi_-
l3/2l\leq-3/2only ψ\psi_-

At l=1/2l=-1/2, the repeated exponent produces an x1/2logxx^{1/2}\log x companion and both local solutions remain square integrable. In the open limit-circle interval 3/2<l<1/2-3/2<l<1/2, a generic self-adjoint extension fixes a real linear combination of the two boundary coefficients. Away from the repeated exponent, the pure Frobenius lines are the two scale-invariant choices. The Friedrichs line is ψ+\psi_+ for l>1/2l>-1/2 and ψ\psi_- for l<1/2l<-1/2. Outside the limit-circle interval, the nonintegrable line defines only an analytic connection zero, not a second self-adjoint spectrum.

At l=0l=0,

ψ+(x,E,0)x,ψ(x,E,0)1.\psi_+(x,E,0)\sim x, \qquad \psi_-(x,E,0)\sim1.

Evaluation at zero gives

Δ(E,0)=y(0,E),Δ+(E,0)=y(0,E).\Delta_-(E,0)=y(0,E), \qquad \Delta_+(E,0)=-y'(0,E).

After normalization, the minus sign cancels between numerator and denominator. Hence the functions reduce exactly to those of Page 1:

D(E,0)=DD(E),D+(E,0)=DN(E).D_-(E,0)=D_{\mathrm D}(E), \qquad D_+(E,0)=D_{\mathrm N}(E).

Thus DD_- is Dirichlet and D+D_+ is Neumann when l=0l=0. They are also the odd and even full-line sectors when the potential is extended evenly as x2M|x|^{2M}; in particular this is automatic for integer MM. The signs should never be guessed from the subscripts.

Zero-energy normalization removes the last scalar ambiguity

Section titled “Zero-energy normalization removes the last scalar ambiguity”

The canonical solution at E=0E=0 is explicitly reducible to a modified Bessel function. At nonexceptional ll where the expressions are finite, the unit-leading-coefficient convention used throughout this chapter gives

Δ(0,l)=1πΓ ⁣(1+2l+12M+2)×(2M+2)12+2l+12M+2,Δ+(0,l)=1πΓ ⁣(12l+12M+2)×(2M+2)122l+12M+2.\begin{aligned} \Delta_-(0,l) ={}& \frac{1}{\sqrt{\pi}}\, \Gamma\!\left( 1+\frac{2l+1}{2M+2} \right) \\ &\times (2M+2)^{ \frac12+\frac{2l+1}{2M+2} }, \\ \Delta_+(0,l) ={}& \frac{1}{\sqrt{\pi}}\, \Gamma\!\left( 1-\frac{2l+1}{2M+2} \right) \\ &\times (2M+2)^{ \frac12-\frac{2l+1}{2M+2} }. \end{aligned}

Define, wherever the denominators are finite,

D±(E,l):=Δ±(E,l)Δ±(0,l).D_\pm(E,l) := \frac{\Delta_\pm(E,l)}{\Delta_\pm(0,l)}.

Then D±(0,l)=1D_\pm(0,l)=1. At exceptional parameters these normalized functions must instead be defined by a declared meromorphic limit or a regularized local basis. For fixed nonexceptional ll and M>1M>1, the order in EE is

μ=M+12M<1,\mu = \frac{M+1}{2M} <1,

so the normalized functions are fixed by their zero divisors:

D(E,l)=n=0(1EEnreg),D+(E,l)=n=0(1EEnalt).\begin{aligned} D_-(E,l) &= \prod_{n=0}^{\infty} \left( 1-\frac{E}{E_n^{\mathrm{reg}}} \right), \\ D_+(E,l) &= \prod_{n=0}^{\infty} \left( 1-\frac{E}{E_n^{\mathrm{alt}}} \right). \end{aligned}

The second line is a product over the zeros of the analytic companion; the label “alt” does not assert self-adjointness outside the domain described above. At M=1M=1, the order is one and a zero-free exponential survives, exactly as Pages 1 and 3 warned.

The integrable model is the quantum KdV/conformal-field-theory system of Bazhanov, Lukyanov, and Zamolodchikov. Its parameters may be written

c=16(ββ1)2,Δp=(pβ)2+c124.\begin{aligned} c &= 1-6(\beta-\beta^{-1})^2, \\ \Delta_p &= \left(\frac{p}{\beta}\right)^2 +\frac{c-1}{24}. \end{aligned}

The homogeneous radial ODE matches the highest-weight, or module-vacuum, QQ-eigenvalue with the following passport:

ODE datumIntegrable-model datum
exponent MMcoupling β2=1/(M+1)\beta^2=1/(M+1)
rotation phase ω=eπi/(M+1)\omega=\ee^{\pi\ii/(M+1)}shift phase q=eπiβ2\mathfrak q=\ee^{\pi\ii\beta^2}
centrifugal label llhighest-weight/twist label p=β2(2l+1)/4p=\beta^2(2l+1)/4
energy EEentire spectral coordinate s=vMEs=v_ME
normalized DD_-module-vacuum Q+Q_+
normalized D+D_+module-vacuum QQ_-
ODE zeros Enreg/altE_n^{\mathrm{reg/alt}}Bethe roots sn+/s_n^{+/-}
order (M+1)/(2M)(M+1)/(2M)order 1/(22β2)1/(2-2\beta^2)

Equivalently,

q=ω,e2πip=ωl+1/2,l=2pβ212.\mathfrak q=\omega, \qquad \ee^{2\pi\ii p}=\omega^{l+1/2}, \qquad l=\frac{2p}{\beta^2}-\frac12.

The phases act before squaring. On the ODE side a Symanzik step rotates xx by ω\omega and hence the energy coordinate by ω2\omega^2; on the integrable side the Baxter shift rotates λ\lambda by q\mathfrak q and hence s=λ2s=\lambda^2 by q2\mathfrak q^2. Since q=ω\mathfrak q=\omega, this explains why Page 5 contains squared phases in the entire-variable functional relations.

The state row is indispensable. The elementary radial potential matches one selected highest-weight eigenvalue; it does not describe every eigenvalue of Q±\mathbf Q_\pm.

A three-zone passport distinguishes the radial ODE determinants and their energies, the normalization-complete ODE/IM parameter bridge, and the module-vacuum Baxter eigenvalues with their Bethe roots.

The determinant–Baxter bridge. ODE theory constructs normalized entire functions from one infinity line and each of two Frobenius origin lines. The middle passport fixes the sign reversal, parameter map, and spectral scale. Only after the homogeneous highest-weight correspondence is declared do the same entire functions become module-vacuum Baxter eigenvalues and their zeros become Bethe roots. No TQTQ or transfer-matrix arrow is used on this page.

The large-variable asymptotic fixes the spectral scale

Section titled “The large-variable asymptotic fixes the spectral scale”

Writing ss as merely “proportional to EE” leaves a physically relevant normalization unfixed. Put

a0=Γ(μ)Γ(μ+12)π.a_0 = -\frac{ \Gamma(-\mu)\Gamma(\mu+\tfrac12) }{ \sqrt{\pi} }.

On the ODE side, as E|E|\to\infty with arg(E)<π|\arg(-E)|<\pi,

logD(E,l)a02(E)μ.\log D_-(E,l) \sim \frac{a_0}{2}(-E)^\mu.

The normalized module-vacuum Baxter eigenvalue has, as s|s|\to\infty in the corresponding cut sector,

logQ+(s,p)a0(M+1)×Γ ⁣(12μ)2μ(s)μ.\begin{aligned} \log Q_+(s,p) \sim{}& a_0(M+1) \\ &\times \Gamma\!\left(\frac{1}{2\mu}\right)^{2\mu} (-s)^\mu. \end{aligned}

Both powers use the principal logarithm on that sector: (z)μ=exp[μLog(z)](-z)^\mu=\exp[\mu\Log(-z)] with π<arg(z)<π-\pi<\arg(-z)<\pi.

Set E=s/vME=s/v_M and match the two coefficients. This gives

vM=(2M+2)1/μΓ ⁣(12μ)2.v_M = (2M+2)^{-1/\mu} \Gamma\!\left(\frac{1}{2\mu}\right)^{-2}.

It is often convenient to retain the square-root scale

νM=(2M+2)1/(2μ)Γ ⁣(12μ)1,vM=νM2,\nu_M = (2M+2)^{-1/(2\mu)} \Gamma\!\left(\frac{1}{2\mu}\right)^{-1}, \qquad v_M=\nu_M^2,

so that λ=νME\lambda=\nu_M\sqrt E. The branch of E\sqrt E does not affect Q±Q_\pm because they are entire in s=λ2s=\lambda^2.

Matching the leading asymptotic is necessary but not sufficient for the ODE/IM equality. The established correspondence also matches the functional relation, analyticity, zero distribution, and the normalization at zero. Page 5 exposes the functional part of that lock.

The sign reversal is controlled by one involution

Section titled “The sign reversal is controlled by one involution”

The equation depends on ll only through l(l+1)l(l+1) and is invariant under

l1l.l\longmapsto-1-l.

This exchanges the two Frobenius roles and gives

Δ+(E,l)=Δ(E,1l),D+(E,l)=D(E,1l).\begin{aligned} \Delta_+(E,l) &= \Delta_-(E,-1-l), \\ D_+(E,l) &= D_-(E,-1-l). \end{aligned}

Under the parameter map, the same involution is

pp,p\longmapsto-p,

and the normalized module-vacuum eigenvalues obey, wherever both sides are finite,

Q(s,p)=Q+(s,p).Q_-(s,p)=Q_+(s,-p).

This explains, rather than merely memorizes, the correspondence Q±DQ_\pm\leftrightarrow D_\mp. The exceptional set is larger than the single repeated-exponent point: it is exactly

l+12=±[m1+(M+1)m2],m1,m2Z0.l+\frac12 = \pm\bigl[m_1+(M+1)m_2\bigr], \qquad m_1,m_2\in\mathbb Z_{\geq0}.

At these values the preferred Frobenius or normalization data can mix, develop poles, or require logarithmic solutions. The point l=1/2l=-1/2 is the most visible member because the exponents coincide. Analytic continuation or a regularized basis is then required; the paired analysis belongs to Page 6.

The determinant identity immediately converts zeros:

Q+(sn+,p)=0sn+vM=Enreg,Q(sn,p)=0snvM=Enalt.\begin{aligned} Q_+(s_n^+,p)=0 &\quad\Longleftrightarrow\quad \frac{s_n^+}{v_M} =E_n^{\mathrm{reg}}, \\ Q_-(s_n^-,p)=0 &\quad\Longleftrightarrow\quad \frac{s_n^-}{v_M} =E_n^{\mathrm{alt}}. \end{aligned}

For the regular real problem with nonexceptional l>1/2l>-1/2, the first sequence is positive, discrete, and simple. Through the established dictionary this proves those properties for the roots of the selected vacuum Q+Q_+-eigenvalue. It says nothing comparable about arbitrary states or arbitrary integrable models.

The Weyl law also transports directly:

Enregn1/μsn+n1/μ.E_n^{\mathrm{reg}} \asymp n^{1/\mu} \quad\Longrightarrow\quad s_n^+ \asymp n^{1/\mu}.

Thus the continuum Bethe roots have precisely the density required for an entire function of order μ\mu. The root divisor plus Q+(0,p)=1Q_+(0,p)=1 then reconstructs the function in the genus-zero range.

No Bethe equation has yet been used. On Page 5, evaluating the normalized TQTQ identity at s=sn±s=s_n^\pm produces the phase constraint on neighboring rotated values. That condition is necessary, but roots alone still do not prove existence, admissibility, completeness, or the choice of integrable state.

For M=2M=2,

β2=13,μ=34,q=eπi/3,\beta^2=\frac13, \qquad \mu=\frac34, \qquad \mathfrak q=\ee^{\pi\ii/3},

and

v2=64/3Γ ⁣(23)2.v_2 = 6^{-4/3} \Gamma\!\left(\frac23\right)^{-2}.

At l=0l=0, one has p=1/12p=1/12, so

Q+ ⁣(s,112)=DD ⁣(sv2),Q ⁣(s,112)=DN ⁣(sv2).\begin{aligned} Q_+\!\left(s,\frac1{12}\right) &= D_{\mathrm D}\!\left(\frac{s}{v_2}\right), \\ Q_-\!\left(s,\frac1{12}\right) &= D_{\mathrm N}\!\left(\frac{s}{v_2}\right). \end{aligned}

The Q+Q_+ roots are v2v_2 times the half-line Dirichlet levels, and the QQ_- roots are v2v_2 times the Neumann levels.

This example should not be confused with Page 3’s larger family x4+gx2+αxx^4+gx^2+\alpha x. That family has an exact Symanzik parameter orbit, but no equality with the same BLZ QQ-eigenvalues follows. A model, state, spectral scale, functional system, and matching asymptotic passport would all have to be supplied.

Calling every determinant a Q-function. Entirety and a spectral zero set are necessary ODE data, not an integrable-model identification. The operator, state, parameter map, scale, functional relation, asymptotics, and normalization must all match.

Confusing roots with spatial nodes. A Bethe root is a zero in ss of a scalar QQ-eigenvalue. A node is a zero in xx of a wavefunction at fixed energy; a turning point is a zero of the classical momentum.

Forgetting the state. The elementary radial equation matches the highest-weight/module-vacuum eigenvalue. Higher qKdV states require ODEs with additional apparent singularities, often called monster potentials.

Treating the companion determinant as automatically self-adjoint. D+D_+ is a useful analytic connection function away from its exceptional parameters. Its zeros are a physical spectrum only after an admissible endpoint domain is declared; which of D±D_\pm is Friedrichs changes at l=1/2l=-1/2.

1. Separate the three Q-objects. Explain why an operator Q(λ)\mathbf Q(\lambda) is not determined by one eigenvalue, and why a scalar eigenvalue is not determined by its zeros without growth and normalization data.

Solution

An operator has eigenvalues on all states, together with their common eigenvectors and algebraic relations; one scalar function supplies only one diagonal entry. A zero divisor determines an entire function only up to a zero-free factor. In the present genus-zero range, the order bound reduces that factor to a constant, and Q(0)=1Q(0)=1 fixes the constant.

2. Prove the radial zero criterion. For real nonexceptional l>1/2l>-1/2, show both directions of

Δ(E,l)=0one solution is regular at zeroand recessive at infinity.\Delta_-(E_*,l)=0 \quad\Longleftrightarrow\quad \begin{gathered} \text{one solution is regular at zero}\\ \text{and recessive at infinity} \end{gathered}.
Solution

The Wronskian vanishes exactly when y(,E,l)y(\,\cdot\,,E_*,l) and ψ+(,E,l)\psi_+(\,\cdot\,,E_*,l) are linearly dependent. The first is recessive at infinity and the second spans the xl+1x^{l+1} regular origin line in the stated range, so dependence produces one solution with both properties. Conversely, any solution with both properties must be proportional to each one-dimensional canonical line, so their Wronskian vanishes.

3. Recover the Page 1 pair. At l=0l=0, derive the raw endpoint Wronskians and show that normalization gives D=DDD_-=D_{\mathrm D} and D+=DND_+=D_{\mathrm N}.

Solution

With ψ+x\psi_+\sim x and ψ1\psi_-\sim1,

Wr[y,ψ+]x=0=y(0,E),Wr[y,ψ]x=0=y(0,E).\begin{aligned} \Wr[y,\psi_+]\big|_{x=0} &=y(0,E), \\ \Wr[y,\psi_-]\big|_{x=0} &=-y'(0,E). \end{aligned}

Dividing each expression by its value at E=0E=0 gives the normalized Dirichlet and Neumann endpoint functions. The two minus signs in the Neumann ratio cancel.

4. Check the zero-energy constants. Wherever both sides are finite, use Euler’s reflection formula to prove

Δ(0,l)Δ+(0,l)=2l+1sin ⁣[π(2l+1)/(2M+2)].\Delta_-(0,l)\Delta_+(0,l) = \frac{2l+1}{ \sin\!\left[\pi(2l+1)/(2M+2)\right] }.
Solution

Put a=(2l+1)/(2M+2)a=(2l+1)/(2M+2). Multiplication of the two displayed constants gives

2M+2πΓ(1+a)Γ(1a).\frac{2M+2}{\pi} \Gamma(1+a)\Gamma(1-a).

Since Γ(1+a)Γ(1a)=πa/sin(πa)\Gamma(1+a)\Gamma(1-a)=\pi a/\sin(\pi a), the product is (2M+2)a/sin(πa)(2M+2)a/\sin(\pi a), which is the claimed expression. The identity then extends meromorphically in ll.

5. Match the orders. Starting from β2=1/(M+1)\beta^2=1/(M+1), show

μ=M+12M=122β2.\mu = \frac{M+1}{2M} = \frac{1}{2-2\beta^2}.

Why is M>1M>1 exactly 0<β2<1/20<\beta^2<1/2?

Solution

Solving for MM gives M=β21M=\beta^{-2}-1. Therefore

M+12M=β22(β21)=122β2.\frac{M+1}{2M} = \frac{\beta^{-2}}{2(\beta^{-2}-1)} = \frac{1}{2-2\beta^2}.

For positive MM, the inequality M>1M>1 is equivalent to β2>2\beta^{-2}>2, hence 0<β2<1/20<\beta^2<1/2.

6. Derive the spectral scale. Match the two large-variable asymptotics and recover vMv_M.

Solution

Substituting E=s/vME=s/v_M into the ODE asymptotic gives the coefficient a0/(2vMμ)a_0/(2v_M^\mu). Equating it to the Baxter coefficient yields

12vMμ=(M+1)Γ ⁣(12μ)2μ.\frac{1}{2v_M^\mu} = (M+1) \Gamma\!\left(\frac{1}{2\mu}\right)^{2\mu}.

Solving for vMv_M gives

vM=(2M+2)1/μΓ ⁣(12μ)2.v_M = (2M+2)^{-1/\mu} \Gamma\!\left(\frac{1}{2\mu}\right)^{-2}.

7. Translate the quartic passport. Compute β2,μ,p,v2\beta^2,\mu,p,v_2 for M=2,l=0M=2,l=0 and identify both root sequences.

Solution

Direct substitution gives

β2=13,μ=34,p=112,\beta^2=\frac13, \qquad \mu=\frac34, \qquad p=\frac1{12},

and

v2=64/3Γ ⁣(23)2.v_2 = 6^{-4/3}\Gamma\!\left(\frac23\right)^{-2}.

The Q+Q_+ roots are v2EnDv_2E_n^{\mathrm D} and the QQ_- roots are v2EnNv_2E_n^{\mathrm N}.

8. Reject a premature identification. For x4+gx2+αxx^4+gx^2+\alpha x, list data still missing before a radial determinant can be called one of the BLZ Baxter functions on this page.

Solution

One must supply an integrable model and commuting QQ-operator, select a state, map (g,α)(g,\alpha) to model parameters, fix the spectral scale and zero normalization, match the entire-function asymptotics, and prove the same functional relation and analytic passport. Symanzik covariance alone provides none of those model-side data.